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Jawab:
Penjelasan dengan langkah-langkah:
S = {1, 2, 3, 4, 5, 6}
n(S) = 6
a. A = Kejadian munculnya mata dadu 4
A = {4}
n(A) = 1
P(A) = n(A)/n(S) = 1/6
b. B = Kejadian munculnya mata dadu genap
B = {2, 4, 6}
n(B) = 3
P(B) = n(B)/n(S) = 3/6 = 1/2
c. C = Kejadian munculnya mata dadu prima
C = {2, 3, 5}
n(C) = 3
P(C) = n(C)/n(S) = 3/6 = 1/2
d. D = Kejadian munculnya mata dadu faktor dari 6
D = {1, 2, 3, 6}
n(D) = 4
P(D) = n(D)/n(S) = 4/6 = 2/3
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